OpenEuphoria

Re: Speed test

• Posted by Igor Kachan <kinz at peterlink.ru> Sep 04, 2001
• 457 views

Hello Ricardo,

> I'm afraid I don't understand what do you call
> "vertical slicing". If one uses parallel sequences,
> let's say x, y, z, then there is only one way to
> refer to each element of these, namely x[i], etc.
> Please give an example of what you mean.

This case is described in refman.doc file.
See please below:

--program vert.ex
sequence a,c

a={{01, 02, 03, 04},  --> row 1
   {05, 06, 07, 08},  --> row 2
   {09, 10, 11, 12},  --> row 3
   {13, 14, 15, 16}}  --> row 4
--   1   2   3   4    <-- columns 1..4
   
? a[3][2..3] -- this is a simple expression for any row
   
function b(sequence s, integer n)
 sequence v
  v=repeat(0,length(s))
     for i=1 to length(s) do
       v[i]=s[i][n]
     end for
 return v
end function

  c=b(a,3)  -- but to take a column you must write
? c [3..4]  -- your own function.
	      -- this is a 'vertical slicing problem'
	      -- in Euphoria
	    
function d(sequence s, integer n, integer m, integer l)
 sequence v
  v=repeat(0,length(s))
     for i=1 to length(s) do
       v[i]=s[i][n]
     end for
 return v[m..l]
end function

? d(a,3,3,4)-- this complicated expression for columns
	      -- has 10 elements
  	      -- but simple one for rows has same 10 elements,
	      -- see above
-- end of program

Maybe, these functions above are useful too, use if so.

Regards,
Igor Kachan
kinz at peterlink.ru