OpenEuphoria

Re: Why equal(x[n], x[n..n])=0 ?

• Posted by Jason Gade <jaygade at yah?o.c?m> Sep 25, 2007
• 720 views

Fernando Bauer wrote:
> 
> Hi Pete,
> 
> Pete Lomax wrote:
> > 
> > Jason Gade wrote:
> > > Because when you say s[3..3] you are saying, "bring me one item in a
> > > bucket".
> > > It's not mutually exclusive. You can carry one thing with or without the
> > > bucket.
> > > You can always take the item out of the bucket after it is brought to you.
> > > 
> > I like that analogy. A slice asks for a bucket with n items in it. You've
> > always
> > got the bucket, whether it has 97, 4, 1, or 0 things in it.
> > And a thing in a bucket is not the same as said thing not in a bucket.
> And that is the problem! Sometimes you expect a thing out of the bucket and
> you receive within the bucket.
> 
> > 
> > Regards,
> > Pete
> Regards,
>    Fernando

I understand what you are saying, and after a certain point the answer becomes
"because that's the way it is!" Which is rarely satisfying to give or receive,
but...

I still think it adheres to the "principle of least surprise" anyway, unlike a
few other aspects of the language.

--
A complex system that works is invariably found to have evolved from a simple
system that works.
--John Gall's 15th law of Systemantics.

"Premature optimization is the root of all evil in programming."
--C.A.R. Hoare

j.