Re: What is the equivalent EU expression
- Posted by Mark Brown <mabrown at SENET.COM.AU> Mar 16, 2000
- 451 views
Hi Brian One small thing with your example for prasanta. I seem to remember that inputs to C functions must all be atoms so I think the "integer arg1" might need to be "atom arg1". I seem to remember getting an error something like "inputs to C functions must be atoms" once before. If I'm wrong please ignore Mark ----- Original Message ----- From: Brian Jackson <bjackson at 2FARGON.COM> To: <EUPHORIA at LISTSERV.MUOHIO.EDU> Sent: Thursday, March 16, 2000 1:33 Subject: Re: What is the equivalent EU expression > On Wed, 15 Mar 2000 21:51:30 -0500, Prasanta Chakraborty > <prasanta at WRITEME.COM> wrote: > > >Hi, > > > >I am trying to call a C func from EU, the C Func is described as: > >SQLAllocHandle(SQLSMALLINT HandleType, SQLINTEGER InputHandle, SQLINTEGER > >FAR *OutputHandle); > >where SQLINTEGER is of type long. > > > >What will be the equivalent EU code. > > > >Regards, > >Prasanta. > > Prasanta, > > What you ask is actually a 2-part process. First you must define the c > function (and the DLL it lives in) in the context of your program using > open_dll() and define_c_func(). Here's an example: > > global constant wsock32 = open_dll("wsock32.dll") > global constant func_WSAStartup = define_c_func(wsock32,"WSAStartup", > {C_SHORT,C_POINTER},C_INT) > > This "links" the DLL to your program, and declares func_WSAStartup as an > external C function that takes C types SHORT(euphoria integer) and POINTER > (euphoria atom) as arguments, and returns a type INT(euphoria atom). > > Now to use the function, you would need to do this: > > integer arg1 > atom arg2 > atom returnValue > > -- you need to assign the appropriate values to arg1 and arg2 here > returnValue = c_func(func_WSAStartup, {arg1, arg2}) > > Also, Fabio Ramirez has written a very nice MySQL interface for Euphoria > which may either be exactly what you need, or at least give you some good > examples of how to wrap SQL API functions using Euphoria. > > Hope this helps! > > Brian