Short Circuit Question
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Can someone exlain why line to of the output actually tests both 1 and 3,
shouldn't just test 1?
is it interpreted as ((1 or 2) and 3) or as (1 or (2 and 3)) ?
Daniel Kluss
----------output
1 2 3 true
1 3 true
1 true
1 2 true
-----------program
without warning
function ptr(atom num)
printf(1,"%d ",{num})
return num
end function
if ptr(1) and ptr(2) and ptr(3) then puts(1,"true\n") else puts(1,"false\n") end
if
if ptr(1) or ptr(2) and ptr(3) then puts(1,"true\n") else puts(1,"false\n") end
if
if ptr(1) or ptr(2) or ptr(3) then puts(1,"true\n") else puts(1,"false\n") end
if
if ptr(1) and ptr(2) or ptr(3) then puts(1,"true\n") else puts(1,"false\n") end
if
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<DIV><FONT face=Arial size=2>Can someone exlain why line to of the output
actually tests both 1 and 3, shouldn't just test 1?</FONT></DIV>
<DIV><FONT face=Arial size=2>is it interpreted as ((1 or 2) and 3) or as (1
or (2 and 3)) ?</FONT></DIV>
<DIV><FONT face=Arial size=2>Daniel Kluss</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>----------output</FONT></DIV>
<DIV><FONT face=Arial size=2>1 2 3 true<BR>1 3 true<BR>1 true<BR>1 2
true<BR>-----------program</DIV></FONT>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>without warning<BR>function ptr(atom
num)<BR> printf(1,"%d
",{num})<BR> return num<BR>end
function</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>if ptr(1) and ptr(2) and ptr(3) then
puts(1,"true\n") else puts(1,"false\n") end if</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>if ptr(1) or ptr(2) and ptr(3) then
puts(1,"true\n") else puts(1,"false\n") end if</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>if ptr(1) or ptr(2) or ptr(3) then puts(1,"true\n")
else puts(1,"false\n") end if</FONT></DIV>
<DIV> </DIV>
<DIV><FONT face=Arial size=2>if ptr(1) and ptr(2) or ptr(3) then
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