OpenEuphoria

Re: Gaussian Distribution Using Dice

• Posted by "Juergen Luethje" <j.lue at gmx.de> Jul 31, 2004
• 488 views

Just 2 small comments (see below).

Lewis Townsend wrote:

> ck,
>
> Here is my solution but it doesn't do any graffing.
> I think it is mathematically correct but it could be wrong.
> I just wrote it real quick. It prints up something that
> looks right to me.
>
> }}}
<eucode>
> include get.e
>
> function sum( sequence s )
> 	atom a
> 	a = 0
> 	for i = 1 to length( s ) do
> 		a+= s[i]
> 	end for
> 	return a
> end function
>
> constant NumOfDice = 3
> constant NumOfSides = 6
>
> constant MaximumRoll = NumOfDice * NumOfSides
>
> sequence chances, dice
> chances = repeat( 0, MaximumRoll )
> dice = repeat( 1, NumOfDice )
>
> integer roll

Local variable roll is not used.

> for d = 1 to power( NumOfSides, NumOfDice ) do
> 	chances[sum(dice)] += 1
> 	dice[1]+=1
> 	for i = 1 to NumOfDice -1 do
> 		if dice[i] > NumOfSides then
> 			dice[i] = 1
> 			dice[i+1] += 1

                -- this makes it faster:
                else
                        exit

> 		end if
> 	end for
> end for
>
>
> printf( 1, "The distobution of %d %d sided dice rolls:\n",
> {NumOfDice,NumOfSides} )
> puts( 1, "Value\tChance\n" )
> for i = 1 to length( chances ) do
> 	printf(1, "%d\t%d\n", i&chances[i] )
> end for
> if wait_key() then end if
> </eucode>
{{{


Regards,
   Juergen