Re: getOpenFileName
- Posted by dcole Feb 11, 2011
- 1654 views
WJ1N said...
filename = getOpenFileNameEx( Window1, -- parent window "e:\\euphoria\\stocks\\*.dat", -- no default name { "Text Files", "*.TXT", -- text files "Data Files","*.DAT", "All Files", "*.*" }, -- everything else { {ofnFilterIndex,2} } )
try this
This worked for me unless i misunderstand what you want.
Johnny
Yes that's what I want. It does work thank you very much.
Don Cole