Re: Record for Most Subscripts
- Posted by mattlewis (admin) Jul 23, 2009
- 770 views
Critic said...
You could at least do this:
object whatever whatever = stacks[t][2][x][2][y][z] f = find(whatever[2],faces[1]) s = find(whatever[1],suits[1])
But this really is pretty advanced stuff. Derek did not know about this either.
There you go again. You just can't resist the premature micro-optimization, huh?
Matt
PS:
IHBT
YHBT
WHBT