Re: Record for Most Subscripts

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Critic said...

You could at least do this:

  object whatever 
  whatever = stacks[t][2][x][2][y][z] 
  f = find(whatever[2],faces[1]) 
  s = find(whatever[1],suits[1]) 

But this really is pretty advanced stuff. Derek did not know about this either.

There you go again. You just can't resist the premature micro-optimization, huh?

Matt

PS:
IHBT
YHBT
WHBT

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