1. Re: Rob: Out of memory + broken shorthand assignment operators in expressio
- Posted by Vincent <darkvincentdude at yahoo.com>
Nov 18, 2005
-
Last edited Nov 19, 2005
Robert Craig wrote:
>
> Vincent wrote:
> > This is quite interesting because I've written small programs
> > simular to that, and Euphoria runs out of memory (every time)
> > at loop 141441051. I didnt think of reporting it, because I
> > thought my computer was running out of memory. Adjusting the
> > swap file size did nothing.
> >
> > My computer is a 2.66 GHz Pentium 4 Northwood 512 KB L2 cache;
> > 512 MB DDR SD-RAM @ 333 MHz; 512 MHz front-side bus; Windows XP
> > SP 2.
>
> Hmm... 141441051 x 4 bytes per element = 565,764,204 bytes
> which already exceeds your RAM. Plus where is the O/S
> supposed to reside? Plus append() must sometimes make a full
> copy of your sequence plus extra, when it moves the data
> to a new larger contiguous block.
>
But it crashes with the same value regardless if the swap file is
2 GB or 4 GB. Doesn't Euphoria utilize the swap file when it uses
all the system memory? It could'nt have used all 4 GB of RAM+swap
file? The way your talking... if append() copied the sequence,
then maybe just a little more than 1 GB would be required.
> > I discovered an issue that has to do with assignment operators
> > failing to work in conditional or loop expressions. My guess
> > is that this been a issue since they were introduced in
> > Euphoria v2.1.
> >
> > For example:
> > }}}
<eucode>
> > -- this code runs
> > integer i, f
> >
> > i = 0
> > f = 0
> >
> > if i = i + 1 then
> > end if
> >
> > while f = f + 1 do
> > end while
> >
> > machine_proc(26,0) -- wait_key
> > </eucode>
{{{
> > But...
> > }}}
<eucode>
> > -- this code fails with an error
> > integer i, f
> >
> > i = 0
> > f = 0
> >
> > if i += 1 then
> > end if
> >
> > while f += 1 do
> > end while
> >
> > machine_proc(26,0) -- wait_key
> > </eucode>
{{{
> >
> > The same thing happens with -=, /=, *=, and
> > &= (with sequences).
>
> f += 1 is not an expression. It's a statement.
> That's why you get an error message.
I see... but I thought they both worked the same?
I mean, 'i = i + 4' produces the same result as
'i += 4', etc.
>
> Regards,
> Rob Craig
> Rapid Deployment Software
> <a href="http://www.RapidEuphoria.com">http://www.RapidEuphoria.com</a>
Regards,
Vincent
