1. dumb C question (part 2)
Another dumb C translation question >
// in C
}
else if(playOK && (code == HC_SKIP)) curmess++;
-- in Euphoria
elsif and_bits(playOK , code) = HC_SKIP then
curmess += 1
I understand how to do things like this pretty well but,
heres where I get confused
// in C
s = !s;
-- in Euphoria
would it be:
if not s then
or
s = not s (hehe just joking)
I'm lost and it seems the most simple things throw me.....
Please, Help.
euman at bellsouth.net
Euman
2. Re: dumb C question (part 2)
On Fri, 20 Apr 2001, Euman wrote:
> Another dumb C translation question >
> heres where I get confused
>
> // in C
>
> s = !s;
>
> -- in Euphoria
>
> would it be:
>
> if not s then
> or
> s = not s (hehe just joking)
Yes.
These give the same results:
// C
#include <stdio.h>
int main()
{
int s;
s = 3;
s = !s;
printf("%d",s);
}
-- Euphoria
atom s
s = 3
s = not 3
printf(1,"%d",s)
Regards,
Irv
3. Re: dumb C question (part 2)
- Posted by snetxa at hotmail.com
Apr 21, 2001
Correct me if I'm wrong but I would have thought that
> // in C
> }
> else if(playOK && (code == HC_SKIP)) curmess++;
would have given
elsif playOK and ( code = HC_SKIP ) then
curmess += 1
end if
It is & for bit_and and && for logical_and in C?
Bruce.
P.S. Yeah, it me. I couldn't stand to be offline so I've resubscribed
through my hotmail account.
