1. Eu Doc's
Hi Robert Hi All,
I am not new to Euphoria but I have not used Euphoria in a very long
time. Anyway I am back with Euphoria again and I can't remember some
things about it. I clipped this from the documentation but I am not
understanding something here and I know this may seem simple but here it
goes anyway. In Example 2 below what variable type is "i" in the line
"for i = 1 to length(x) do". I tried this same simple for loop and
declared i as an integer but when I run the program it says that I am
trying to redefine that variable. If anyone could give me a kick start
back into Eu I would greatly appreciate it.
sequence
Syntax: i = sequence(x)
Description: Return 1 if x is a sequence else return 0.
Comments: This serves to define the sequence type. You can also call it
like an ordinary function to determine if an object is a sequence.
Example 1:
sequence s
s = {1,2,3}
Example 2:
if sequence(x) then
sum = 0
for i = 1 to length(x) do
sum = sum + x[i]
end for
else
-- x must be an atom
sum = x
end if
See ya on the Net
MindPower
2. Re: Eu Doc's
> Hi Robert Hi All,
> I am not new to Euphoria but I have not used Euphoria in a very long
> time. Anyway I am back with Euphoria again and I can't remember some
> things about it. I clipped this from the documentation but I am not
> understanding something here and I know this may seem simple but here it
> goes anyway. In Example 2 below what variable type is "i" in the line
> "for i = 1 to length(x) do". I tried this same simple for loop and
> declared i as an integer but when I run the program it says that I am
> trying to redefine that variable. If anyone could give me a kick start
> back into Eu I would greatly appreciate it.
the for..do..end for statement automatically declares the counter
variable. That means that you do not need to (and indeed cannot)
declare it yourself. You can use the counter (i) within the for loop
but not outside it.
Thomas Parslow (PatRat) ICQ #:26359483
Rat Software
http://www.rat-software.com/
Please leave quoted text in place when replying
3. Re: Eu Doc's
> Hi Thomas,
> Thank you for the information but that still does not tell me what type
> of variable "i" is???? I guess my point is what type of variable does
> the length() routine return? I thought it was an integer but I guess it
> is some other type????
>
>
> See ya on the Net
> MindPower
sorry, missed the question :)
Euphoria doesn't really have data types like most other languages,
in the example you gave i is an atom (it's also an Integer
because it never takes on a fractional value).
Thomas Parslow (PatRat) ICQ #:26359483
Rat Software
http://www.rat-software.com/
Please leave quoted text in place when replying
