1. RE: Help testing transparentBlt function
> -----Original Message-----
> From: Thomas Parslow (PatRat) [mailto:patrat at rat-software.com]
> It requires win32lib for a reason I haven't
> been able to figure out yet (i don't use any win32lib
> functions but it just
> doesn't work if i don't include it).
You're testing for an error incorrectly. From the docs on define_c_func:
... A small integer, known as a routine id, will be returned, or -1 if the
function can't be found....
The reason win32lib affected you is that it has already linked several
routines, so you're not getting 0 (which is a valid routine id).
Matt Lewis
2. RE: Help testing transparentBlt function
> In the app I'm writing Win32Lib's transBlt has become a major
> bottleneck, so I'm looking for a better (faster) way to do it.
> The TransparentBlt function in MSIMG32.DLL seems perfect for the job,
> but I'm not totally sure how will this is supported throughout the
> various versions of windows.
> I've attached a quick test, could anyone who has the time run this and
> tell me the result along with any information you can give about your
> system (OS version ect). It requires win32lib for a reason I haven't
> been able to figure out yet (i don't use any win32lib
> functions but it just
> doesn't work if i don't include it).
>
Hi Thomas,
try this instead ...
-----------------------
include dll.e
constant MSIMG32 = open_dll("msimg32.dll")
if MSIMG32 = 0 then
puts(1,"Unable to load the msimg32.dll :(\nPress any key to continue...")
? gets(0)
abort(1)
end if
constant funcTransparentBlt =
define_c_func(MSIMG32,"TransparentBlt",{C_POINTER,C_INT,C_INT,C_INT,C_INT,C_
POINTER,C_INT,C_ INT,C_INT,C_INT,C_UINT},C_ULONG)
if funcTransparentBlt < 0 then
puts(1,"Unable to use TransparentBlt function :(\nPress any key to
continue...")
? gets(0)
abort(1)
end if
puts(1,"Everything is fine, TransparentBlt can be used :)\nPress any key to
continue...")
? gets(0)
---------------------
You don't need win32lib if you test the return of define_c_func() correctly.
A zero return is valid for this function, because it returns -1 if an error
is detected.
-----------
cheers,
Derek Parnell
