1. ROBERT CRAIG
-- Attention Robert:
-- I am using Euphoria ver 2.0
-- I am having a problem with compiling a if/elsif/else
-- Please explain to me what I am doing wrong
integer a, b, c, d
a = 1
b = 2
c = 3
d = 4
----------------- this will compile OK
if a = 1 then
? d
end if
if a = 2 then
? d
end if
if a = 3 then
? d
end if
----------------- If you try to compile this
----------------- compiler will report an error
----------------- but this should be ok
-- if a = 1 then
-- ? d
-- elsif a = 2 then
-- ? d
-- else a = 3 then -- <<----- this fails
-- ? d
-- end if
----------------- by changing the else to elsif
----------------- compiler will not report an error
----------------- but I am not sure this compiles to the same thing
if a = 1 then
? d
elsif a = 2 then
? d
elsif a = 3 then -- <<----- changed else to elsif
? d
end if
---------------
Thank You for your time
Bernie
2. Re: ROBERT CRAIG
Bernie,
There is no such thing as 'else ... then' clause. Your line is interpreted as a
simple assignment 'a = 3' followed by 'then' WITHOUT matching 'if' or 'elsif'.
jiri
3. Re: ROBERT CRAIG
DAAAAAA !!!!
My brain is geting too old, my eyes are too weak and my tongue keeps
getting caught in my eye tooth and I can't see what I am saying.
Thanks Bernie
