1. Re: Forward Definitions
- Posted by "Cuny, David" <David.Cuny at DSS.CA.GOV> Feb 24, 1999
- 415 views
David Guy wrote: >>3. Change the scope of routine_id to the run time scope, not compile time. > ... > If it's not too much trouble, could you give a simple example of what you > mean by the above statement, and how/why it would/could be a problem? routine_id returns an identifier to a user-defined routine. It will fail (return -1) under one of the following circumstances: 1. The routine is not defined, or local to another include file; 2. The routine is not part of the current scope; or 3. The routine is a built-in, such as gets or puts. routine_id can only "see" routines that have been defined up to the routine that it is embedded into. For example: procedure foo() end procedure procedure test( sequence procname ) if routine_id( procname ) = -1 then puts( 1, "can't see " & procname & "\n" ) else puts( 1, "can see " & procname & "\n" ) end if end procedure procedure bar() end procedure test( "puts" ) test( "foo" ) test( "bar" ) if you run this code, you will get the following results: can't see puts can see foo can't see bar 'puts' cannot be seen because it is a built-in function. This behavior certainly suprised me when I first saw it, but I suspect that there are compelling reasons for being that way. My guess is that 'routine_id' is probably pretty gruesomely coded, and we are lucky to have *anything* like it at all. 'foo' can be seen, because it was defined before 'test'. Since 'test' can see 'foo', so can 'routine_id'. 'bar' cannot be seen, because it was defined after 'test'. Since 'test' cannot see 'foo', neither can 'routine_id'. The way I would *prefer* the code to work is: 'bar' can be seen, because it is *called* after 'bar' is defined. There are various reasons for the preference; most of them can be worked around by using routine_id at the point were I need the routine id. -- David Cuny