1. Dynamic names
Hi everyone,
Case: In a given situation I want to add 1 to an specified integer.
Something like this:
integer atbat, RBIplayer1, RBIplayer2, RBIplayer3.....RBIplayer 10, etc.
if X > 0 then
if atbat = player1 then RBIplayer1 = RBIplayer1 + 1 end if
if atbat = player2 then RBIplayer2 = RBIplayer2 + 1 end if
....
if atbat = player10 then RBIplayer10 = RBIplayer10 + 1 end if
end if
Is it possible to simplify it to something like this:
if X > 0 then
RBI[atbat] = RBI[atbat] + 1
end if
Bye,
Jasper.
2. Re: Dynamic names
Jasper Holshuijsen wrote:
> Is it possible to simplify it to something like this:
>
> if X > 0 then
> RBI[atbat] = RBI[atbat] + 1
> end if
Urm, yes... it seems simple enough to test, am I missing something here?
If you're feeling especially reckless, you can also write:
RBI[atbat] += (X > 0)
-- David Cuny
3. Re: Dynamic names
Hi David,
I tried
RBI[atbat] = RBI[atbat] + 1
and it didn't work. I thought I was using a wrong statement. I can't give
you the error message right now because I'm not behind the computer on
which I'm developing my program. Can I conclude from your reaction that I'm
on the right way? (For this case then 
)
Bye,
Jasper.
4. Re: Dynamic names
Hi Jasper,
----- Original Message -----
From: <Jasper_Holshuijsen at dsw.nl>
To: "EUforum" <EUforum at topica.com>
Subject: Dynamic names
>
> Case: In a given situation I want to add 1 to an specified integer.
>
> Something like this:
>
> integer atbat, RBIplayer1, RBIplayer2, RBIplayer3.....RBIplayer 10, etc.
>
> if X > 0 then
> if atbat = player1 then RBIplayer1 = RBIplayer1 + 1 end if
> if atbat = player2 then RBIplayer2 = RBIplayer2 + 1 end if
> ....
> if atbat = player10 then RBIplayer10 = RBIplayer10 + 1 end if
> end if
>
> Is it possible to simplify it to something like this:
>
> if X > 0 then
> RBI[atbat] = RBI[atbat] + 1
> end if
>
Sure is. This is a classic use of sequences. Remember that a sequence can be
used to implement an array. In this case a list of scores.
He is a bit of code to demonstrate it.
----------
sequence RBI
constant MAXPLAYERS = 10
integer atbat
. . .
-- Initialise the scores
RBI = repeat(0, MAXPLAYERS)
. . .
-- Increase score
if X > 0 then
if atbat > 0 and atbat <= MAXPLAYERS then
RBI[atbat] += 1
else
printf(1, "Logic error: 'atbat' = %d\n", atbat)
end if
end if
------------
Derek.
5. Re: Dynamic names
Thanks,
I haven't tried it yet but I think an array is exactly the answer on my
question.
Jasper.
Derek Parnell
<ddparnell@big To: EUforum <EUforum at topica.com>
pond.com> cc:
Subject: Re: Dynamic names
08-10-2001
13:43
Please respond
to EUforum
Hi Jasper,
----- Original Message -----
From: <Jasper_Holshuijsen at dsw.nl>
To: "EUforum" <EUforum at topica.com>
Sent: Monday, October 08, 2001 6:51 PM
Subject: Dynamic names
>
> Case: In a given situation I want to add 1 to an specified integer.
>
> Something like this:
>
> integer atbat, RBIplayer1, RBIplayer2, RBIplayer3.....RBIplayer 10, etc.
>
> if X > 0 then
> if atbat = player1 then RBIplayer1 = RBIplayer1 + 1 end if
> if atbat = player2 then RBIplayer2 = RBIplayer2 + 1 end if
> ....
> if atbat = player10 then RBIplayer10 = RBIplayer10 + 1 end if
> end if
>
> Is it possible to simplify it to something like this:
>
> if X > 0 then
> RBI[atbat] = RBI[atbat] + 1
> end if
>
Sure is. This is a classic use of sequences. Remember that a sequence can
be
used to implement an array. In this case a list of scores.
He is a bit of code to demonstrate it.
----------
sequence RBI
constant MAXPLAYERS = 10
integer atbat
. . .
-- Initialise the scores
RBI = repeat(0, MAXPLAYERS)
. . .
-- Increase score
if X > 0 then
if atbat > 0 and atbat <= MAXPLAYERS then
RBI[atbat] += 1
else
printf(1, "Logic error: 'atbat' = %d\n", atbat)
end if
end if
------------
Derek.
6. Re: Dynamic names
Jasper Holshuijsen wrote:
> I tried
> RBI[atbat] = RBI[atbat] + 1
> and it didn't work. I thought I was using
> a wrong statement.
One thing that can be really helpful is to use Euphoria's trace facility.
I've found it invaluable for debugging code.
> Can I conclude from your reaction that I'm
> on the right way? (For this case then )
Yes.
Good luck!
-- David Cuny
