1. silly question
Hi all, my brains must be off now (or still), because i can't figure this one.
If i
use
while match(";",title) do
title = title[1..match(";",title)-1] &" "&
title[match(";",title)+1..length(title)]
end while
then match() is fine. But to look for a atom numerically, i must use find():
while find(9,title) do
title = title[1..find(9,title)-1] &" "& title[find(9,title)+1..length(title)]
end while
What difference, other than i can spec a numeric in find(), since i cannot
enter a "13" as a char from the keybd,, which means i cannot enter a string
containing a CR either, except as a escaped char?
At the moment, i don't know why i cannot get my brain around this one,,
maybe it's too obvious..
Kat
2. Re: silly question
Hi Kat,
as far as i got it from the manual concerning find(x,s): if the
elements of s are numbers (chars), then x has to be a number (char). If
the elements of s are strings, then x has to be a string.
Have a nice day, Rolf
3. Re: silly question
Kat,
if 'title' is a string (i.e a sequence with numbers 0 < numbers < 256),
then you may find a CR by
find(13,title) or a LF by find(10,title).
an alternative is: match({13},title) or even match({13,10},title) to
find CR or CRLF.
Have a nice day, Rolf
4. Re: silly question
Kat, sounds to me like you are trying to find a letter in a string, right?
so, I guess you have been unable to get this:
s = find( ";", aString)
to work. Well, find() locates an atom in a string.
in euphoria, ";" is like saying {75} (I don't know the Char code for ;.)
becuase anything in " " is a sequence. If you put a single character in
single quotes, ';' then it should work.
Try calling
s = find(';', aString)
ciao
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