1. Problem Solved: (was: Newcomer with a problem)
- Posted by Ralf Nieuwenhuijsen <nieuwen at XS4ALL.NL>
Jan 25, 1998
-
Last edited Jan 26, 1998
Mutal recursion is possible with Euphoria in the most current version (Alpha
2)
You can get it from RDS' site.
How ?
Well, with routine id's.
Example:
procedure mutal_A (integer id, sequence arg)
puts (1,"Calling procedure:")
print (1, id)
puts (1,"With the arguments:\n")
print (1,arg)
-- Look this up!
call_proc (id, arg)
end procedure
procedure mutal_B (integer id, sequence arg)
puts (1,"Calling procedure:")
print (1, id)
puts (1,"With the arguments:\n")
print (1,arg)
-- Look this up!
call_proc (id, arg)
end procedure
-- Now let's use these weird looking routines..
integer a,b
a = routine_id ("Mutal_A")
b = routine_id ("Mutal_B")
call_proc (a, {b,{a,{b,{ } } } })
-- We now called routine a, that called routine b, that called routine a,
that called routine b.
Here's who wrote what so we can all look it up...
>At 01:50 25/01/98 +0000, David B. Williams wrote
>
>>Hello, everyone. I'm new to Euphoria, and have been having a problem
>>that I can't seem to find the answer to in the documentation. It's
>>probably there, I'm just horrible at finding things like that.
>>
>>I'm wondering about function and procedure declaration. Currently,
>>I've got a function and a procedure. They both call the other at one
>>point in their block, but because one appears before the other, the
>>interpreter says the second one is undefined (and therefore will not
>>continue running the program).
>>
>
>Unfortunately mutual recursion is not allowed in euphoria.
>A routine may call itself but not another routine that calls it.
>
>Graeme.
>
