1. About atom memories
I tried this program:
object x
for i = 1024*1024 to 1000000000000000000000 by 1024*1024 do
x = repeat(i+111111111.111111111111111111111111111111111, i)
? i
printf(1, "%20.20f\n", x[i])
x = getc(0)
end for
after i = 10MB, I saw the memory usage (using TaskInfo2000),
it was 41376 KB ~~ 40.4 MB
So one atom just use 4 bytes, not 8 bytes?
And the precision is still 16 digits!
(I get 121596871.11111110000000000000 at the last line)
If it's like that, EU is better that I thought!
2. Re: About atom memories
Aku writes:
> object x
> for i = 1024*1024 to 1000000000000000000000 by 1024*1024 do
> x = repeat(i+111111111.111111111111111111111111111111111, i)
> ? i
> printf(1, "%20.20f\n", x[i])
> x = getc(0)
> end for
>
> after i = 10MB, I saw the memory usage (using TaskInfo2000),
> it was 41376 KB ~~ 40.4 MB
>
> So one atom just use 4 bytes, not 8 bytes?
> And the precision is still 16 digits!
When i is 10 million, x will have 10 million 4-byte pointers to
a single floating-point value.
Regards,
Rob Craig
Rapid Deployment Software
http://www.RapidEuphoria.com
