1. Color Modes...(vesa20.e)
1) I know that 65k means 65,000, and that 16.7M means 16,700,000, but
in terms of number of colors in a graphics mode, is 65k literally
65,000, or 16.7M literally 16,700,000? I would like to know so I can
incorporate it into my graphics library...which I now am finished with
the 'rough draft,' and am now writing the demo programs for it. Any
help is appreciated, it's just that computer numbers can be tricky.
With 1 Kb actually being 1024 bytes and all.
2) Is there any way to read a 24-bit bitmap/image under DOS with
current libraries? I'm thinking of adding 24-bit support to my
library.
Thanks all, and please help,
Mike Hurley
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2. Re: Color Modes...(vesa20.e)
- Posted by Undetermined origin c/o LISTSERV administrator
May 08, 1999
-
Last edited May 09, 1999
EUPHORIA at LISTSERV.MUOHIO.EDU wrote:
> 1) I know that 65k means 65,000, and that 16.7M means 16,700,000, but
> in terms of number of colors in a graphics mode, is 65k literally
> 65,000, or 16.7M literally 16,700,000? I would like to know so I can
> incorporate it into my graphics library...which I now am finished with
> the 'rough draft,' and am now writing the demo programs for it. Any
> help is appreciated, it's just that computer numbers can be tricky.
> With 1 Kb actually being 1024 bytes and all.
Probably, 65K is actually using 2^16 colors, or 65536. 16.7M is 24-bit
color, or 16777216 colors.
>
>
> 2) Is there any way to read a 24-bit bitmap/image under DOS with
> current libraries? I'm thinking of adding 24-bit support to my
> library.
>
> Thanks all, and please help,
> Mike Hurley
>
> _________________________________________________________
> Do You Yahoo!?
> Get your free @yahoo.com address at http://mail.yahoo.com
3. Re: Color Modes...(vesa20.e)
From: Mike Hurley
>1) I know that 65k means 65,000, and that 16.7M means 16,700,000, but
>in terms of number of colors in a graphics mode, is 65k literally
>65,000, or 16.7M literally 16,700,000? I would like to know so I can
>incorporate it into my graphics library...which I now am finished with
>the 'rough draft,' and am now writing the demo programs for it. Any
>help is appreciated, it's just that computer numbers can be tricky.
>With 1 Kb actually being 1024 bytes and all.
#0000FFFF = 65,535
#00FFFFFF = 16,777,215
<g> when in doubt, check with a calculator.
>2) Is there any way to read a 24-bit bitmap/image under DOS with
>current libraries? I'm thinking of adding 24-bit support to my
>library.
I think neil.e's load_bitmap() does that... Yup! Sure does. 
4. Re: Color Modes...(vesa20.e)
Message text written by Mike Hurley
>I know that 65k means 65,000, and that 16.7M means 16,700,000, but
in terms of number of colors in a graphics mode, is 65k literally
65,000, or 16.7M literally 16,700,000?<
65 K refers to 65,536 which is 2 to the 16th power (2^16, 16-bit color). =
16.7 million refers to 16,777,216 which is 2^24 (as in 24-bit color). So=
,
in general, 2^(bit depth) =3D number of colors.
Colin Taylor
PS. Since Dan unsubscribed and Jiri boarded that jet, it has gotten
awfully quiet on the list! :-I
