1. append and &
- Posted by George Walters <gwalters at sc.rr.com> Mar 21, 2002
- 418 views
Can someone explain the difference between these two statements ----------------------------- sequence a a = "a" for i = 1 to 10 a = append(a,"a") end for ---------------------------- sequence a a = "a" for i = 1 to 10 a = a & "a" end for ---------------------------- I'm having some conceptual confusion with results from above as compared with 'vectors', 'matrices' from prior languages. george
2. Re: append and &
- Posted by Irv Mullins <irvm at ellijay.com> Mar 21, 2002
- 396 views
On Thu, 21 Mar 2002 06:43:31 -0500 George Walters <gwalters at sc.rr.com> wrote: > > Can someone explain the difference between these two statements > ----------------------------- > sequence a > a = "a" > for i = 1 to 10 > a = append(a,"a") > end for > ---------------------------- > sequence a > a = "a" > for i = 1 to 10 > a = a & "a" > end for > ---------------------------- Ignoring the fact that neither example works (you need a 'do' in there!:), the first creates an 'array' of ten 1-character strings: "a","a","a","a"...... while the second simply appends characters to the original string: "aaaaaaaaaaa" You can print the second as a string: puts(1,a), but you have to index into the first before you can print an element. print a[2] => "a" More interesting would be: a = "Ant" a &= "Cat" a &= "Dog" a &= "Rat" This does a standard string concatenation: puts(1,a) => "AntCatDogRat" However: a = "Ant" a = append(a,"Cat") a = append(a,"Dog") a = append(a,"Rat") does NOT result in what I would expect: an array of 3 strings ["Ant","Cat","Dog","Rat"], instead, it creates a string containing nested sub-strings: ["Ant{"Cat","Dog","Cat"]"], so trying to print a[2] gives 'n', not "Cat" as expected. i.e: a[1] => 'A' a[2] => 'n' a[3] => 't' -- ready for the surprise? a[4] => "Cat" a[5] => "Dog".... To create an array of strings, you need to declare the first as follows: a = {"Ant"} -- note the braces a = append(a,"Cat") a = append(a,"Dog")... now, puts(1,a[2]) => "Cat" The exact same results can be had from: a = {"Ant"} a &= {"Cat"} a &= {"Dog"} ... Regards, Irv
3. Re: append and &
- Posted by Derek Parnell <ddparnell at bigpond.com> Mar 21, 2002
- 379 views
----- Original Message ----- From: "George Walters" <gwalters at sc.rr.com> To: "EUforum" <EUforum at topica.com> Subject: append and & > > Can someone explain the difference between these two statements > ----------------------------- > sequence a > a = "a" > for i = 1 to 10 > a = append(a,"a") > end for > ---------------------------- > sequence a > a = "a" > for i = 1 to 10 > a = a & "a" > end for > ---------------------------- > > I'm having some conceptual confusion with results from above as compared > with 'vectors', 'matrices' from prior languages. append() always increases the result by exactly one element. & always increases the results by the length of the source. In both cases, atoms are considered to have a length of 1 for this exercise. Thus a = append(b, c) always adds a single element, c, as a new element to the end of b. eg: a = {1,2,3} a = append(a,a) ==> {1,2,3,{1,2,3}} The length increases by 1. a = append(a,a) ==> {1,2,3,{1,2,3},{1,2,3,{1,2,3}}} The length increases by 1. And a = b & c always just joins c to the back of b, increasing the length by how ever long c is. a = {1,2,3} a = a & a ==> {1,2,3,1,2,3} The length increases by 3. a = a & a ==> {1,2,3,1,2,3,1,2,3,1,2,3} The length increases by 6. For sequences, a = append(a,a) is equivalent to a &= {a} For atoms, a = append(a,a) is equivalent to a &= a. ----------- Derek.
4. Re: append and &
- Posted by George Walters <gwalters at sc.rr.com> Mar 21, 2002
- 388 views
nice tutorial, thanks... I've been getting mighty confused on indexing into the tables i've been creating. george ----- Original Message ----- From: "Irv Mullins" <irvm at ellijay.com> To: "EUforum" <EUforum at topica.com> Subject: Re: append and & > > On Thu, 21 Mar 2002 06:43:31 -0500 > George Walters <gwalters at sc.rr.com> wrote: > > > > > Can someone explain the difference between these two statements > > ----------------------------- > > sequence a > > a = "a" > > for i = 1 to 10 > > a = append(a,"a") > > end for > > ---------------------------- > > sequence a > > a = "a" > > for i = 1 to 10 > > a = a & "a" > > end for > > ---------------------------- > > Ignoring the fact that neither example works (you need a 'do' in there!:), > the first creates an 'array' of ten 1-character strings: "a","a","a","a"...... > while the second simply appends characters to the original string: > "aaaaaaaaaaa" > > You can print the second as a string: puts(1,a), but you have to index into the first before you can print an element. > print a[2] => "a" > > More interesting would be: > a = "Ant" > a &= "Cat" > a &= "Dog" > a &= "Rat" > This does a standard string concatenation: puts(1,a) => "AntCatDogRat" > > However: > a = "Ant" > a = append(a,"Cat") > a = append(a,"Dog") > a = append(a,"Rat") > > does NOT result in what I would expect: an array of 3 strings ["Ant","Cat","Dog","Rat"], > instead, it creates a string containing nested sub-strings: > ["Ant{"Cat","Dog","Cat"]"], > so trying to print a[2] gives 'n', not "Cat" as expected. i.e: > a[1] => 'A' > a[2] => 'n' > a[3] => 't' > -- ready for the surprise? > a[4] => "Cat" > a[5] => "Dog".... > > To create an array of strings, you need to declare the first as follows: > a = {"Ant"} -- note the braces > a = append(a,"Cat") > a = append(a,"Dog")... > > now, puts(1,a[2]) => "Cat" > > The exact same results can be had from: > a = {"Ant"} > a &= {"Cat"} > a &= {"Dog"} ... > > Regards, > Irv > > > >
5. Re: append and &
- Posted by George Walters <gwalters at sc.rr.com> Mar 21, 2002
- 404 views
thanks Derek.... george ----- Original Message ----- From: "Derek Parnell" <ddparnell at bigpond.com> To: "EUforum" <EUforum at topica.com> Subject: Re: append and & > > ----- Original Message ----- > From: "George Walters" <gwalters at sc.rr.com> > To: "EUforum" <EUforum at topica.com> > Sent: Thursday, March 21, 2002 10:43 PM > Subject: append and & > > > > Can someone explain the difference between these two statements > > ----------------------------- > > sequence a > > a = "a" > > for i = 1 to 10 > > a = append(a,"a") > > end for > > ---------------------------- > > sequence a > > a = "a" > > for i = 1 to 10 > > a = a & "a" > > end for > > ---------------------------- > > > > I'm having some conceptual confusion with results from above as compared > > with 'vectors', 'matrices' from prior languages. > > > append() always increases the result by exactly one element. > > & always increases the results by the length of the source. > > In both cases, atoms are considered to have a length of 1 for this exercise. > > Thus a = append(b, c) always adds a single element, c, as a new element to > the end of b. > eg: > > a = {1,2,3} > a = append(a,a) > ==> {1,2,3,{1,2,3}} The length increases by 1. > a = append(a,a) > ==> {1,2,3,{1,2,3},{1,2,3,{1,2,3}}} The length increases by 1. > > And a = b & c always just joins c to the back of b, increasing the length by > how ever long c is. > > a = {1,2,3} > a = a & a > ==> {1,2,3,1,2,3} The length increases by 3. > a = a & a > ==> {1,2,3,1,2,3,1,2,3,1,2,3} The length increases by 6. > > For sequences, a = append(a,a) is equivalent to a &= {a} > > For atoms, a = append(a,a) is equivalent to a &= a. > > ----------- > Derek. > > > >