1. RE: pass by reference Karl
- Posted by Bernie Ryan <xotron at localnet.com> Feb 12, 2002
- 494 views
kbochert at ix.netcom.com wrote: > -------Phoenix-Boundary-07081998- > Content-type: text/plain; charset=ISO-8859-1 > Content-transfer-encoding: 8bit > > Hi Irv Mullins, you wrote on 2/12/02 10:26:37 AM: > > >If I call foo(integer x) as follows: > > > >x = 3 > >foo(x) > >? x => 3 > > > >No matter what happens inside the mysterious foo, x is still what it was > >before calling the function. > >Even if foo sets x to 99, it's only 99 while inside the foo routine. > >So foo is working with a copy of x, not the real x. > > > >Pass-by_reference passes the actual variable, not a copy, so that > >foo(var integer x) > > x = 99 > >end > > > >x = 3 > >foo(x) > >? x => 99 > > > >The variable IS changed within the routine, and remains changed > >afterward. > > > >Regards, > >Irv > > In my implementation, pass-by reference is accomplished by > the caller. That is: > > procedure foo (sequence x) > x = x[2..3] > end procedure > > sequence s = "test" > foo (s) > -- s still equals "test" > > foo (!!s) > -- s now equals "es" > > Library routines can never do something behind your > back. > > The other not-so-minor detail is that only sequences > can be passed by reference. Karl: What happens when a user does slicing, append, prepend on the sequence that is passed. Don't forget that sequences are dynamic and are reallocated dynamically. Bernie
2. Re: RE: pass by reference Karl
- Posted by Derek Parnell <ddparnell at bigpond.com> Feb 12, 2002
- 489 views
kbochert at ix.netcom.com wrote: > > In my implementation, pass-by reference is accomplished by > the caller. That is: > > procedure foo (sequence x) > x = x[2..3] > end procedure > > sequence s = "test" > foo (s) > -- s still equals "test" > > foo (!!s) > -- s now equals "es" > > Library routines can never do something behind your > back. I'm not so sure Karl. Lets say that I have a routine like this... procedure X(object a) if sequence(a) then a = ConvertToNumber(a) end if GlobalX += a end procedure then I call this using your method... s = "23" X(!!s) this should either crash with an assignment error (assigning an atom to seq) or change the sequence S to now be an atom. However, calling it normally is quite safe... s = "23" X(s) --------- Cheers, Derek Parnell
3. RE: pass by reference Karl
- Posted by kbochert at ix.netcom.com Feb 12, 2002
- 480 views
-------Phoenix-Boundary-07081998- Hi Bernie Ryan, you wrote on 2/12/02 1:20:32 PM: > >Karl: > What happens when a user does slicing, append, prepend > on the sequence that is passed. Don't forget that > sequences are dynamic and are reallocated dynamically. >Bernie > Thanks for pointing that out -- I had overlooked it totally. The good news is that I have now managed to correct the slicing case: procedure foo (sequence s) s = s[3..] end procedure sequence t = "Hello" foo (!!t) ?t -- => "llo" Time and again I run into these issues that seem to be killers, only to discover that the code to do them seems to be already there. I think Rob did NOT choose pass-by-value because it was the easy choice for implementation. My motivation for adding pass-by-value is to allow class methods to be passed a 'this reference' which refers to the instance to be modified. My original implementation accomplishes this nicely because no class method ever changes the structure of the instance. Given the ease of handling slices, I suspect that all cases could be handled, but the risk of deep problems grows, so I am somewhat reluctant to proceed. Thanks for the bug find Karl -------Phoenix-Boundary-07081998---
4. Re: RE: pass by reference Karl
- Posted by kbochert at ix.netcom.com Feb 12, 2002
- 483 views
-------Phoenix-Boundary-07081998- Hi Derek Parnell, you wrote on 2/12/02 4:21:17 PM: > >kbochert at ix.netcom.com wrote: > > In my implementation, pass-by reference is accomplished by > the caller. That is: > > procedure foo (sequence x) > x = x[2..3] > end procedure > > sequence s = "test" > foo (s) > -- s still equals "test" > > foo (!!s) > -- s now equals "es" > > Library routines can never do something behind your > back. > >I'm not so sure Karl. Lets say that I have a routine like this... > > procedure X(object a) > if sequence(a) then > a = ConvertToNumber(a) > end if > > GlobalX += a > end procedure > >then I call this using your method... > > s = "23" > X(!!s) > >this should either crash with an assignment error (assigning an atom to >seq) or change the >sequence >S to now be an atom. > >However, calling it normally is quite safe... > > s = "23" > X(s) > >--------- >Cheers, >Derek Parnell > I hadn't considered that possibility. Surprisingly it seems to work reasonably! integer q = 1 sequence t = "hello" procedure X(object a) if sequence(a) then a = 5 end if q += a ?q --=> 6 end procedure X (!!t) ?t -- => "hello" The procedure never actually modifies the sequence, only the identifier. the 'a=5' line creates a new entity. A bit confusing perhaps but what can you do? I guess that PBR only happens when you pass a sequence AND the subroutine treats it as a sequence. Karl -------Phoenix-Boundary-07081998---