1. To Robert Craig ... help !!!
Rob,
Amid all your woes comes another one.
BUT U CAN SOLVE I AM SURE >> !!
Please ...... how do I get code to recognise gets() input. ?
include get.e
include file_ln.e
constant SCREEN = 1
constant KEYBRD = 0
constant TRUE=1
sequence line,name
object exit_code
atom w
puts(SCREEN, "Enter your Directory name here: ")
line = gets(KEYBRD) -------------------- CAN I GET THIS BESIDE "c:\\" below
???
print(SCREEN, line)
puts(SCREEN, line[1..$-1])
puts(SCREEN, line)
clear_screen()
name=line
printf(1,"%s",{name})
w=wait_key()
function look_at(sequence path_name,sequence entry)
printf(1,"%s\\%s: %d\n\t\t",{path_name,entry[D_NAME], entry[D_SIZE]})
return 0
end function
exit_code = walk_dir("c:\\" , routine_id("look_at"), TRUE)
w=wait_key()
get the "c:\\" to accept my input of gets() ????
like ................ "c:\\" & my input ...
hope you can help.
sometime ????
cheers les.r.
2. Re: To Robert Craig ... help !!!
Try this. Note that \\ is needed inside a Euphoria string,
to get a single backslas character, but the user must type \
not \\
include get.e
include file.e
constant TRUE=1
sequence line
integer exit_code, w, line_count
line_count = 1
function look_at(sequence path_name,sequence entry)
printf(1,"%s\\%s: %d\n", {path_name, entry[D_NAME], entry[D_SIZE]})
line_count += 1
if remainder(line_count, 20) = 0 then
w = wait_key()
end if
return 0
end function
puts(1, "enter path (without C:\\):\n")
line = gets(0) -- will be a sequence with \n on the end
-- (unless the user types control-Z)
-- user must type single \ not \\
line = line[1..$-1] -- drop the \n
puts(1, "c:\\" & line & ":\n\n")
exit_code = walk_dir("c:\\" & line, routine_id("look_at"), TRUE)
puts(1, "Type Enter to quit\n")
w=wait_key()
Regards,
Rob Craig
Rapid Deployment Software
http://www.RapidEuphoria.com
