1. RE: Faster way?
Faster way?
Don't know but you could try this...
Regards,
Mike
integer wsColor
wsColor = 255
image = (image = wsColor) * background + (image != wsColor) * image
dubetyrant at hotmail.com wrote:
> Hello,
> I'm wondering if there is a more efficient(meaning faster) way of
> comparing each element of a sequence with each element of another
> sequence of the same size.Im matching an image with a background
> image,and
> any whitespace I find,I want to convert to the background image.
>
>
> sequence image
>
> sequence background
>
> for i= 1 to length(image) by 1 do
>
> for j=1 to length(image[1]) by 1 do
> temp=compare(image[i][j],background[1][j])
>
> if image[i][j]=255 then
> image[i][j]=background[1][j]
>
> end if
>
> end for
> end for
>
>
> Note:Sorry I havent been able to help on some of the other problems
> posted here,its just that I really don't have much experience with
> programming.Maybe someday I'll be able to help out more
> Thanks,
> JDUBE
>
>
vulcan at win.co.nz
2. RE: Faster way?
dubetyrant at hotmail.com wrote:
> Hello,
> I'm wondering if there is a more efficient(meaning faster) way of
> comparing each element of a sequence with each element of another
> sequence of the same size.Im matching an image with a background
> image,and
> any whitespace I find,I want to convert to the background image.
>
>
> sequence image
>
> sequence background
>
> for i= 1 to length(image) by 1 do
>
> for j=1 to length(image[1]) by 1 do
> temp=compare(image[i][j],background[1][j])
>
> if image[i][j]=255 then
> image[i][j]=background[1][j]
>
> end if
>
> end for
> end for
>
>
> Note:Sorry I havent been able to help on some of the other problems
> posted here,its just that I really don't have much experience with
> programming.Maybe someday I'll be able to help out more
> Thanks,
> JDUBE
>
>
i have not played with images yet.
i believe an image when read in would be 1 long sequence, right?
no subsequences in it.unless you have read it in that way because of
memory restrictions. therefor it would not be a 2 dimension table.
you would simply overlay any whitespace found (255) with the image data
at that same location.
also you are using the 'length' function in your loop control statement.
each time this statement is executed so would the length function be
re-calculated.
calculate it once prior to entering the loop would help.
seqsize = length(image)
for i = 1 to seqsize by 1 do
if image[i] = 255 then
image[i] = background[i]
end if
end for
Merry Christmas and Happy New Year to All Euphorians
Rudy
lotterywars
3. RE: Faster way?
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At 02:32 25.12.02 +0000, you wrote:
>
>
>dubetyrant at hotmail.com wrote:
> > Hello,
> > I'm wondering if there is a more efficient(meaning faster) way of
> > comparing each element of a sequence with each element of another
> > sequence of the same size.Im matching an image with a background
> > image,and
<snip>
>also you are using the 'length' function in your loop control statement.
>each time this statement is executed so would the length function be
>re-calculated.
>calculate it once prior to entering the loop would help.
>
>seqsize = length(image)
>for i = 1 to seqsize by 1 do
>if image[i] = 255 then
>image[i] = background[i]
>end if
>end for
>
>Merry Christmas and Happy New Year to All Euphorians
>Rudy
>lotterywars
Actually, this is only true for while loops. for loops use the
length() function only once. Here's a demo:
---------------------------
sequence s
puts(1, "for loop:for i = 1 to length(s) do --accesses length(s) only once\n")
s={1,2,3,4,5}
? s
for i = 1 to length(s) do --accesses length(s) only once
printf(1, "%2d ", {length(s)}) ? s
s = s & i
end for
puts(1, "while length(s) > 2 do --accesses length(s) on each iteration\n")
? s
while length(s) > 2 do --accesses length(s) on each iteration
printf(1, "%2d ", {length(s)}) ? s
s = s[2..length(s)]
end while
I think Rob commented on this a while back.
Bob
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