1. RE: math Question.... how to do a check sum?
Pete Lomax wrote:
>
>
> On Thu, 11 Dec 2003 12:40:57 +0000, shepardmar at yahoo.com wrote:
>
> >the idea is to reduce the sum from the variables so they
> >are under 22
> >
> >ex.
> >
> >if total is 599 then
> >5+9+9 =23 is over 22 so reduce futher 2+3 = 5
> >
> This will do the trick:
<snip>
> ?checksum(170) -- prints 8
> ?checksum(599) -- prints 5
Alternatively, remainder( sum, 22 ) would work.
170 => 16
599 => 5
Matt Lewis
2. RE: math Question.... how to do a check sum?
Hey Pete!
That works perfect!!!!
Thanks.
Pete Lomax wrote:
>
>
> On Thu, 11 Dec 2003 12:40:57 +0000, shepardmar at yahoo.com wrote:
>
> >the idea is to reduce the sum from the variables so they
> >are under 22
> >
> >ex.
> >
> >if total is 599 then
> >5+9+9 =23 is over 22 so reduce futher 2+3 = 5
> >
> This will do the trick:
>
> function checksum(integer c)
> sequence s
> while c>22 do
> s=sprintf("%d",{c})
> c=0
> for i=1 to length(s) do
> c+=s[i]-'0'
> end for
> end while
> return c
> end function
> ?checksum(170) -- prints 8
> ?checksum(599) -- prints 5
>
> Regards,
> Pete
> http://palacebuilders.pwp.blueyonder.co.uk/euphoria.html
>
3. RE: math Question.... how to do a check sum?
Thanks Matt!
I tried your idea too!
Many thanks!!!
Matt Lewis wrote:
>
>
> Pete Lomax wrote:
> >
> >
> > On Thu, 11 Dec 2003 12:40:57 +0000, shepardmar at yahoo.com wrote:
> >
> > >the idea is to reduce the sum from the variables so they
> > >are under 22
> > >
> > >ex.
> > >
> > >if total is 599 then
> > >5+9+9 =23 is over 22 so reduce futher 2+3 = 5
> > >
> > This will do the trick:
>
> <snip>
>
> > ?checksum(170) -- prints 8
> > ?checksum(599) -- prints 5
>
> Alternatively, remainder( sum, 22 ) would work.
>
> 170 => 16
> 599 => 5
>
> Matt Lewis
>
