1. round
- Posted by =?iso-8859-2?B?qWtvZGE=?= <tone.skoda at SIOL.NET> Jun 05, 2000
- 517 views
------=_NextPart_000_0007_01BFCF0D.DFA63740 charset="iso-8859-2" Content-Transfer-Encoding: quoted-printable Could someone give me better round function, that rounds number. 1.4 to 1, 1.6 to 2. -1.7 to -2 etc I have written this one, but can't remeber how to do it better, = simpler. --if positive or negative --returns 1 or -1 global function NumberSign(atom num) if num<0 then return -1 else return 1 end if end function --/topic Utilities --/func abs( a ) --/desc Absolute value. --/ret Absolute value of the atom. global function abs( atom a ) if a < 0 then return -a else return a end if end function --rounds number global function round(atom a) atom fl fl=3Dfloor(a) if abs(a-fl)<0.5 then return fl else return floor(a+NumberSign(a)) end if end function ------=_NextPart_000_0007_01BFCF0D.DFA63740 charset="iso-8859-2" Content-Transfer-Encoding: quoted-printable <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN"> <HTML><HEAD> <META content=3D"text/html; charset=3Diso-8859-2" = http-equiv=3DContent-Type> <META content=3D"MSHTML 5.00.2614.3401" name=3DGENERATOR> <STYLE></STYLE> </HEAD> <BODY bgColor=3D#ffffff> <DIV><FONT face=3DArial size=3D2>Could someone give me better round = function, that=20 rounds number.</FONT></DIV> <DIV><FONT face=3DArial size=3D2>1.4 to 1, 1.6 to 2.</FONT></DIV> <DIV><FONT face=3DArial size=3D2>-1.7 to -2 etc</FONT></DIV> <DIV> </DIV> <DIV><FONT face=3DArial size=3D2>I have written this one, but = can't remeber=20 how to do it better, simpler.</FONT></DIV> <DIV> </DIV> <DIV> </DIV> <DIV><FONT face=3DArial size=3D2>--if positive or negative<BR>--returns = 1 or=20 -1<BR>global function NumberSign(atom num)<BR> if num<0 then = return=20 -1<BR> else return 1 end if<BR>end function</FONT></DIV> <DIV> </DIV> <DIV><FONT face=3DArial size=3D2>--/topic Utilities<BR>--/func abs( a = )<BR>--/desc=20 Absolute value.<BR>--/ret Absolute value of the atom.</FONT></DIV> <DIV> </DIV> <DIV><FONT face=3DArial size=3D2>global function abs( atom a = )<BR> =20 if a < 0 then<BR> return=20 -a<BR> = return a<BR> end if<BR>end function</FONT></DIV> <DIV> </DIV> <DIV><FONT face=3DArial size=3D2><BR>--rounds number<BR>global function = round(atom=20 a)<BR> atom fl</FONT></DIV> <DIV> </DIV> <DIV><FONT face=3DArial size=3D2> fl=3Dfloor(a)<BR> if = abs(a-fl)<0.5 then=20 return fl<BR> else return floor(a+NumberSign(a))<BR> end = if<BR>end=20 ------=_NextPart_000_0007_01BFCF0D.DFA63740--
2. Re: round
- Posted by Rolf Schroeder <r.schr at T-ONLINE.DE> Jun 05, 2000
- 462 views
- Last edited Jun 06, 2000
©koda wrote: > > Part 1.1 Type: Plain Text (text/plain) > Encoding: quoted-printable How about: -------------------------------- function round(atom a) if a < 0 then return floor(a - 0.5) else return floor(a + 0.5) end function -------------------------------- a = 1.3 --> round(a) : 1 a = 1.5 --> riund(a) : 2 a = 1.7 --> round(a) : 2 a = -0.3 --> round(a) : 0 a = -0.5 --> round(a) : -1 a = -0.7 --> round(a) : -1 Have a nice day, Rolf
3. Re: round
- Posted by Lewis Townsend <keroltarr at HOTMAIL.COM> Jun 06, 2000
- 479 views
- Last edited Jun 07, 2000
Hello ©koda, >Could someone give me better round function, that rounds number. >1.4 to 1, 1.6 to 2. >-1.7 to -2 etc > >I have written this one, but can't remeber how to do it better, simpler. I think this will do what you want if I'm understanding your question correctly: function round (object x) return floor (x + 0.5) end function ________________________________________________________________________ Get Your Private, Free E-mail from MSN Hotmail at http://www.hotmail.com
4. Re: round
- Posted by Beaumont Furniss <bfurniss at IHUG.CO.NZ> Jun 07, 2000
- 468 views
On 2000-06-06 EUPHORIA at LISTSERV.MUOHIO.EDU said: EU>Hello ©koda, EU>>Could someone give me better round function, that rounds number. EU>>1.4 to 1, 1.6 to 2. EU>>-1.7 to -2 etc EU>>I have written this one, but can't remeber how to do it better, EU>simpler. EU>I think this will do what you want if I'm understanding your EU>question correctly: EU>function round (object x) EU>return floor (x + 0.5) EU>end function you may also wish to consider the sign of x , as this affects the value returned. --------------------------------------------------------------------------- function abs(object x) -- absolute value of atom/integer -- easily extended to a sequence. -- sqrt(x*x) is almost equivalent. -- or use a for loop. if x<0 then x=-x end if return x end function -------------------------------------------------------------------------- function sgn(object x) -- sign of atom/integer -- for loop required for a sequence. integer s s=0 if x<0 then s=-1 elsif x>0 s=1 else s=0 end if return s end function ---------------------------------------------------------------------- function n_round(object x) -- new rounding function. -- requires a little work to extend to a sequence. return sgn(x)*floor(abs(x)+0.5) end function ------------------------------------------------------------------------ Net-Tamer V 1.11 - Test Drive
5. Re: round
- Posted by Dan B Moyer <DANMOYER at PRODIGY.NET> Jun 06, 2000
- 473 views
- Last edited Jun 07, 2000
Did everyone still making round functions miss Rolf's nicely simple yet complete version? Dan Moyer Rolf wrote: How about: -------------------------------- function round(atom a) if a < 0 then return floor(a - 0.5) else return floor(a + 0.5) end function -------------------------------- a = 1.3 --> round(a) : 1 a = 1.5 --> riund(a) : 2 a = 1.7 --> round(a) : 2 a = -0.3 --> round(a) : 0 a = -0.5 --> round(a) : -1 a = -0.7 --> round(a) : -1 Have a nice day, Rolf
6. Re: round
- Posted by Rolf Schroeder <rolf.schroeder at DESY.DE> Jun 07, 2000
- 471 views
Dan B Moyer wrote: > > Did everyone still making round functions miss Rolf's nicely simple yet > complete version? > > Dan Moyer > > Rolf wrote: > > How about: > -------------------------------- > function round(atom a) > if a < 0 then > return floor(a - 0.5) > else > return floor(a + 0.5) > end function > -------------------------------- > > a = 1.3 --> round(a) : 1 > a = 1.5 --> riund(a) : 2 > a = 1.7 --> round(a) : 2 > a = -0.3 --> round(a) : 0 <-- NO! > a = -0.5 --> round(a) : -1 > a = -0.7 --> round(a) : -1 <-- NO! > > Have a nice day, Rolf Sorry, made a mistake! The code above is wrong! Lewis's is correct! The following works also on sequences: --------------------------------- function round(object x) if atom(x) then return floor(x + 0.5) else for i = 1 to length(x) do return round(x[i]) end for end if end function --------------------------------- Have a nice day, Rolf
7. Re: round
- Posted by "Carl R. White" <cyrek at BIGFOOT.COM> Jun 07, 2000
- 468 views
I just can't resist threads like this... Rolf said: function round_gm(atom x) -- Round to greatest magnitude if x < 0 then return floor(x - 0.5) else return floor(x + 0.5) end if end function Rolf's function 'Carl'-ised function round_gm(object x) -- Round to greatest magnitude return floor(x-.5)*(x<0)+floor(x+.5)*(x>0) end function Carl
8. Re: round
- Posted by Rolf Schroeder <rolf.schroeder at DESY.DE> Jun 07, 2000
- 468 views
"Carl R. White" wrote: > > I just can't resist threads like this... > > Rolf said: > function round_gm(atom x) -- Round to greatest magnitude > if x < 0 then > return floor(x - 0.5) > else > return floor(x + 0.5) > end if > end function > > Rolf's function 'Carl'-ised > function round_gm(object x) -- Round to greatest magnitude > return floor(x-.5)*(x<0)+floor(x+.5)*(x>0) > end function > > Carl Carl, my round() or round_gm() is wrong!! round_gm(-2) returns -3, not -2 ! "Lewis Townsend" wrote: > > I think this will do what you want if I'm understanding your > question correctly: > > function round (object x) > return floor (x + 0.5) > end function and this is correct. Have a nice day, Rolf
9. Re: round
- Posted by Lewis Townsend <keroltarr at HOTMAIL.COM> Jun 07, 2000
- 460 views
Hello, >Carl, my round() or round_gm() is wrong!! round_gm(-2) returns -3, not >-2 ! > >"Lewis Townsend" wrote: > > > > > I think this will do what you want if I'm understanding your > > question correctly: > > > > function round (object x) > > return floor (x + 0.5) > > end function > >and this is correct. > >Have a nice day, Rolf Thanks, one thing that my round function does that may or may not me correct is round -.5 to 0. Depending on who you ask, this maybe should round to -1 instead of 0 but I think it is correct for the most part. later, Lewis Townsend ________________________________________________________________________ Get Your Private, Free E-mail from MSN Hotmail at http://www.hotmail.com
10. Re: round
- Posted by "Carl R. White" <cyrek at BIGFOOT.COM> Jun 08, 2000
- 458 views
On Wed, 7 Jun 2000 15:31:59 +0200, Rolf Schroeder <rolf.schroeder at DESY.DE> wrote: >"Carl R. White" wrote: >> >> Rolf's function 'Carl'-ised >> function round_gm(object x) -- Round to greatest magnitude >> return floor(x-.5)*(x<0)+floor(x+.5)*(x>0) >> end function >> >> Carl > >Carl, my round() or round_gm() is wrong!! round_gm(-2) returns -3, not >-2 ! > >"Lewis Townsend" wrote: > >> I think this will do what you want if I'm understanding your >> question correctly: >> >> function round (object x) >> return floor (x + 0.5) >> end function > >and this is correct. I know. That's why I changed the name to 'round_gm' or 'round to greatest magnitude'. It rounds to the number with the largest _absolute_ value rather than the _largest_ value. Now, what can we do with the following function...? function ceiling(object x) -- mathematical complement of floor() return -floor(-x) end function Carl
11. Re: round
- Posted by Aidan Bindoff <abindoff at ONE.NET.AU> Jun 09, 2000
- 486 views
apologies if my last post was formatted badly, I'll put the equation on one line: Hope that reads better Regards, Aidan