OpenEuphoria: Forum: LDL Cholesterol calculation

1. LDL Cholesterol calculation

Posted by jmduro 1 month ago
1190 views

Here is code to calulate LDL Cholesterol by the Martin-Hopkins formula which works even with high levels of triglycerides or total cholesterol.

It has been checked with EU 4.2.0 development.

include std/console.e 
include std/io.e 
 
constant factor_table= { 
  { 3.5,  3.4, 3.3, 3.3, 3.2, 3.1}, 
  { 4  ,  3.9, 3.7, 3.6, 3.6, 3.4}, 
  { 4.3,  4.1, 4  , 3.9, 3.8, 3.6}, 
  { 4.5,  4.3, 4.1, 4  , 3.9, 3.9}, 
  { 4.7,  4.4, 4.3, 4.2, 4.1, 3.9}, 
  { 4.8,  4.6, 4.4, 4.2, 4.2, 4.1}, 
  { 4.9,  4.6, 4.5, 4.3, 4.3, 4.2}, 
  { 5  ,  4.8, 4.6, 4.4, 4.3, 4.2}, 
  { 5.1,  4.8, 4.6, 4.5, 4.4, 4.3}, 
  { 5.2,  4.9, 4.7, 4.6, 4.4, 4.3}, 
  { 5.3,  5  , 4.8, 4.7, 4.5, 4.4}, 
  { 5.4,  5.1, 4.8, 4.7, 4.5, 4.3}, 
  { 5.5,  5.2, 5  , 4.7, 4.6, 4.5}, 
  { 5.6,  5.3, 5  , 4.8, 4.6, 4.5}, 
  { 5.7,  5.4, 5.1, 4.9, 4.7, 4.5}, 
  { 5.8,  5.5, 5.2, 5  , 4.8, 4.6}, 
  { 6  ,  5.5, 5.3, 5  , 4.8, 4.6}, 
  { 6.1,  5.7, 5.3, 5.1, 4.9, 4.7}, 
  { 6.2,  5.8, 5.4, 5.2, 5  , 4.7}, 
  { 6.3,  5.9, 5.6, 5.3, 5  , 4.8}, 
  { 6.5,  6  , 5.7, 5.4, 5.1, 4.8}, 
  { 6.7,  6.2, 5.8, 5.4, 5.2, 4.9}, 
  { 6.8,  6.3, 5.9, 5.5, 5.3, 5  }, 
  { 7  ,  6.5, 6  , 5.7, 5.4, 5.1}, 
  { 7.3,  6.7, 6.2, 5.8, 5.5, 5.2}, 
  { 7.6,  6.9, 6.4, 6  , 5.6, 5.3}, 
  { 8  ,  7.2, 6.6, 6.2, 5.9, 5.4}, 
  { 8.5,  7.6, 7  , 6.5, 6.1, 5.6}, 
  { 9.5,  8.3, 7.5, 7  , 6.5, 5.9}, 
  {11.9, 10  , 8.8, 8.1, 7.5, 6.7} 
} 
 
-- CT, TG, HDL en g/L 
function martin_hopkins(atom CT, atom TG, atom HDL) 
  integer lig=0, col=0, 
          tg=TG*100 
  -- tg, nonhdl en mg/dL 
  atom factor=5.0, nonhdl=(CT-HDL)*100 
 
  if    (tg<50)                then lig=1 
  elsif (tg>=50)  and (tg<57)  then lig=2 
  elsif (tg>=57)  and (tg<62)  then lig=3 
  elsif (tg>=62)  and (tg<67)  then lig=4 
  elsif (tg>=67)  and (tg<72)  then lig=5 
  elsif (tg>=72)  and (tg<76)  then lig=6 
  elsif (tg>=76)  and (tg<80)  then lig=7 
  elsif (tg>=80)  and (tg<84)  then lig=8 
  elsif (tg>=84)  and (tg<88)  then lig=9 
  elsif (tg>=88)  and (tg<93)  then lig=10 
  elsif (tg>=93)  and (tg<97)  then lig=11 
  elsif (tg>=97)  and (tg<101) then lig=12 
  elsif (tg>=101) and (tg<106) then lig=13 
  elsif (tg>=106) and (tg<111) then lig=14 
  elsif (tg>=111) and (tg<116) then lig=15 
  elsif (tg>=116) and (tg<121) then lig=16 
  elsif (tg>=121) and (tg<127) then lig=17 
  elsif (tg>=127) and (tg<133) then lig=18 
  elsif (tg>=133) and (tg<139) then lig=19 
  elsif (tg>=139) and (tg<147) then lig=20 
  elsif (tg>=147) and (tg<155) then lig=21 
  elsif (tg>=155) and (tg<164) then lig=22 
  elsif (tg>=164) and (tg<174) then lig=23 
  elsif (tg>=174) and (tg<186) then lig=24 
  elsif (tg>=186) and (tg<202) then lig=25 
  elsif (tg>=202) and (tg<221) then lig=26 
  elsif (tg>=221) and (tg<248) then lig=27 
  elsif (tg>=248) and (tg<293) then lig=28 
  elsif (tg>=293) and (tg<400) then lig=29 
  elsif (tg>=400)              then lig=30 
  end if 
 
  if    (nonhdl<100)                   then col=1  
  elsif (nonhdl>=100) and (nonhdl<130) then col=2 
  elsif (nonhdl>=130) and (nonhdl<160) then col=3 
  elsif (nonhdl>=160) and (nonhdl<190) then col=4 
  elsif (nonhdl>=190) and (nonhdl<220) then col=5 
  elsif (nonhdl>=220)                  then col=6 
  end if 
 
  factor = factor_table[lig][col] 
  return CT - HDL - (TG/factor) 
end function 
 
atom CT = prompt_number("Total Cholesterol (g/L):\n", {}) 
atom TG = prompt_number("Triglycerides (g/L):\n", {}) 
atom HDL = prompt_number("HDL Cholesterol (g/L):\n", {}) 
printf(STDOUT, "LDL Cholesterol (g/L): %.3f\n", martin_hopkins(CT, TG, HDL)) 
maybe_any_key()

Jean-Marc

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2. Re: LDL Cholesterol calculation

Posted by axtens_bruce 1 month ago
1152 views

So I thought I'd fiddle with this code and change the big if into a decision table-ish thing.

constant lig_dec_tab = { 
{MININT, 57, 1}, 
{50, 57, 2 }, 
{57, 62, 3 }, 
{62, 67, 4 }, 
{67, 72, 5 }, 
{72, 76, 6 }, 
{76, 80, 7 }, 
{80, 84, 8 }, 
{84, 88, 9 }, 
{88, 93, 10 }, 
{93, 97, 11 }, 
{97, 101, 12 }, 
{101, 106, 13 }, 
{106, 111, 14 }, 
{111, 116, 15 }, 
{116, 121, 16 }, 
{121, 127, 17 }, 
{127, 133, 18 }, 
{133, 139, 19 }, 
{139, 147, 20 }, 
{147, 155, 21 }, 
{155, 164, 22 }, 
{164, 174, 23 }, 
{174, 186, 24 }, 
{186, 202, 25 }, 
{202, 221, 26 }, 
{221, 248, 27 }, 
{248, 293, 28 }, 
{293, 400, 29 }, 
{400, MAXINT, 30 } 
}

and then later

   for i = 1 to length(lig_dec_tab) do 
        if tg > lig_dec_tab[1] and tg < lig_dec_tab[2] then 
            lig = lig_dec_tab[3] 
            exit 
        end if 
    end for

But when I run it I get

C:\TEMP\ldl.ex:67 
<0074>:: Errors resolving the following references: 
    'MININT' (ldl.ex:38) has not been declared. 
    'MAXINT' (ldl.ex:67) has not been declared.

But aren't MININT and MAXINT supposed to internal? It's what the manual says.

-Bruce

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3. Re: LDL Cholesterol calculation

Posted by ghaberek (admin) 1 month ago
1127 views

axtens_bruce said...

But when I run it I get

C:\TEMP\ldl.ex:67 
<0074>:: Errors resolving the following references: 
    'MININT' (ldl.ex:38) has not been declared. 
    'MAXINT' (ldl.ex:67) has not been declared.

But aren't MININT and MAXINT supposed to internal? It's what the manual says.

That document is meant for anyone who wants to dive into the backend C code. Nothing there is exposed back to the frontend.

-Greg

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4. Re: LDL Cholesterol calculation

Posted by ghaberek (admin) 1 month ago
1143 views

Here's my version, which bakes the decision-making values into the table:

constant factor_table= { 
  {   -1, 100, 130,160,190,220,999}, 
  {   50, 3.5, 3.4,3.3,3.3,3.2,3.1}, 
  {   57, 4.0, 3.9,3.7,3.6,3.6,3.4}, 
  {   62, 4.3, 4.1,4.0,3.9,3.8,3.6}, 
  {   67, 4.5, 4.3,4.1,4.0,3.9,3.9}, 
  {   72, 4.7, 4.4,4.3,4.2,4.1,3.9}, 
  {   76, 4.8, 4.6,4.4,4.2,4.2,4.1}, 
  {   80, 4.9, 4.6,4.5,4.3,4.3,4.2}, 
  {   84, 5.0, 4.8,4.6,4.4,4.3,4.2}, 
  {   88, 5.1, 4.8,4.6,4.5,4.4,4.3}, 
  {   93, 5.2, 4.9,4.7,4.6,4.4,4.3}, 
  {   97, 5.3, 5.0,4.8,4.7,4.5,4.4}, 
  {  101, 5.4, 5.1,4.8,4.7,4.5,4.3}, 
  {  106, 5.5, 5.2,5.0,4.7,4.6,4.5}, 
  {  111, 5.6, 5.3,5.0,4.8,4.6,4.5}, 
  {  116, 5.7, 5.4,5.1,4.9,4.7,4.5}, 
  {  121, 5.8, 5.5,5.2,5.0,4.8,4.6}, 
  {  127, 6.0, 5.5,5.3,5.0,4.8,4.6}, 
  {  133, 6.1, 5.7,5.3,5.1,4.9,4.7}, 
  {  139, 6.2, 5.8,5.4,5.2,5.0,4.7}, 
  {  147, 6.3, 5.9,5.6,5.3,5.0,4.8}, 
  {  155, 6.5, 6.0,5.7,5.4,5.1,4.8}, 
  {  164, 6.7, 6.2,5.8,5.4,5.2,4.9}, 
  {  174, 6.8, 6.3,5.9,5.5,5.3,5.0}, 
  {  186, 7.0, 6.5,6.0,5.7,5.4,5.1}, 
  {  202, 7.3, 6.7,6.2,5.8,5.5,5.2}, 
  {  221, 7.6, 6.9,6.4,6.0,5.6,5.3}, 
  {  248, 8.0, 7.2,6.6,6.2,5.9,5.4}, 
  {  293, 8.5, 7.6,7.0,6.5,6.1,5.6}, 
  {  400, 9.5, 8.3,7.5,7.0,6.5,5.9}, 
  {13975,11.9,10.0,8.8,8.1,7.5,6.7} 
} 
 
-- CT, TG, HDL en g/L  
function martin_hopkins(atom CT, atom TG, atom HDL)  
  integer lig=2, col=2, 
          tg=floor(TG*100) 
  -- tg, nonhdl en mg/dL 
  atom factor=5.0, nonhdl=(CT-HDL)*100 
 
  while lig <= length(factor_table) 
      and factor_table[lig][1] < tg do 
    lig += 1 
  end while 
 
  while col <= length(factor_table[1]) 
      and factor_table[1][col] < nonhdl do 
    col += 1 
  end while 
 
  factor = factor_table[lig][col] 
  return CT - HDL - (TG/factor) 
end function

-Greg

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