OpenEuphoria

1. still on namespace

• Posted by mexzony Dec 29, 2010
• 1058 views

if color = 1 then  
    puts(1, "Red")  
elsif color = 2 then  
    puts(1, "Green")  
else   
    puts(1, "Blue")  
end if  

look at the code above and the switch statement below

 
switch color do  
    case 1 then  
        puts(1, "Red")  
    case 2 then  
        puts(1, "Green")  
    case else  
        puts(1, "Blue")  
end switch  

now my question is this,in the if statement the condition is that if color is equql to 1 then we output the string "Red".in the equivalent switch statement after switch color we say case i then puts(1,"Red).is it that in case 1 the value returned will be 1 and then red will be output to the screen and the other case 2 the value 2 will be returned. suppose in the if statement i were to replace the color = 1 with color = 4 would i now say in the switch statement case 4 then puts(1, "Red"). also pls explain the fallthru statement.thanks

3. Re: still on namespace

• Posted by irv Dec 29, 2010
• 971 views

if color = 1 then puts(1,"RED") -- is the same as: 
 
switch color do 
  case 1 then puts(1,"RED")  

if color were set to = 4 (or 5, or 6, or -1 etc.) then the else statement would be activated, printing "blue". Therefore, if you can't provide for an exact match for every situation, then the else statement should probably print something like "Some other color!"

Now, suppose you wanted to print "RED" if color was 1 or color was 4.

switch color do 
  case 1,4 then puts(1,"RED") 
  case 2 then ... 

You can have more than one value in a case, just separate with commas. You can see how this might be better than having to code:

if color = 1 or color = 4 then ... 

especially when there might be 10 or more possibilities to check!