OpenEuphoria

2. Re: String sequence characters and appending clarity

• Posted by mattlewis (admin) Nov 08, 2010
• 1384 views

sequence s, ss 
s = "Hello " 
 
s &= "Fred"     --ok 
puts(1,s) 
 
ss = append(s, " Flintstone") --not ok, sequence found inside character string 
 
puts(1,ss) 

Append adds the second parameter as an element to the end of the first parameter, so you'd have:

s = { 'F', 'r', 'e', 'd', " Flinstone"} 

For this operation, you need to use the concatenation operator, '&'.

Matt

4. Re: String sequence characters and appending clarity

• Posted by DerekParnell (admin) Nov 08, 2010
• 1392 views

Because append and concatenate are not the same thing.

concatenate

Join together two objects. The resulting length is the sum of the objects' lengths.

append

Add the entire second object as one element to the first object. The resulting length is the length of the first object plus 1.

sequence A = {'a', 'b', 'c'} 
sequence B = {'d', 'e', 'f'} 
sequence C 
 
C = A & B --> {'a', 'b', 'c', 'd', 'e', 'f'}, length is now 6. 
-- You can see that each element of B has been 'added' to A  
 
C = append(A, B) --> {'a', 'b', 'c', {'d', 'e', 'f'}}, length is now 4. 
-- You can see that B has been added as a single element to A. 
 

6. Re: String sequence characters and appending clarity

• Posted by _tom (admin) Nov 10, 2010
• 1339 views

Here is a table that I intend to add to the documentation:

Basic Sequence Operations

Starting with two sequences:

x = {1,2,3,4,5} 
y = {'a','b','c'} 

A tremendous wealth of sequence operations are possible:

? x[1] -- is 1
? x[$] -- is 5

? x[1..3] -- is {1,2,3}
? x[2..4] -- is {2,3,4}
? x[3..$] -- is {3.4.5}

? x & y -- is {1,2,3,4,5,'a','b','c'}

? splice(x,y,2} -- is {1,'a','b','c',3,4,5}

? remove(x,2) -- is {1,3,4,5}
? remove(x,2,4) -- is {1,5}

? replace(x,y,2) -- is {1,'a','b','c',3,4,5}
? replace(x,y,2,4) -- is {1,'a','b','c',5}

? prepend(x, y ) -- is {{'a','b','c'},1,2,3,4,5}

? insert(x,y,2} -- is {1,{'a','b','c'},2,3,4,5}

? append(x,y) -- is {1,2,3,4,5,{'a','b','c'}}