1. regex.e find_all

The find_all() function in regex is supposed to return an atom >0< if there are no matching sub strings; however, it returns an empty sequence. I suppose that this doesn't really matter as you can test for the length of the sequence; however, the test > if atom(Obj) where Obj is an object returned by find_all() should be TRUE if find_all returned an atom. The test is always FALSE no matter what find_all discovers. here is the code --------------------------> 

#!/home/jd/euphoria/bin/eui              
 
-- euphoria 4.0 running on ubuntu 9 
 
include std/pretty.e 
include std/regex.e as re 
 
sequence str_1,str_2 
object b,c 
integer fn = open("/home/jd/euphoria/jd_src/test_regex.dat","r") 
 
str_1 = "<property name=\"title\" translatable=\"yes\">My Window</property>" 
str_2 = "<property name=\"title\" translatable=\"yes\">My Window/property>" 
                                                                |missing '<' 
re:regex r2 = re:new(">[a-zA-Z0-9 ]+<") 
 
b = re:find(r2,str_1) 
c = re:find(r2,str_2) 
? b 
? c 
b = re:find_all(r2,str_1) 
c = re:find_all(r2,str_2) 
? b 
? c

here is the output ------> 

~/euphoria/jd_src>./reg_test.ex 
{ 
  {42,52}               <---find() finds one! 
} 
-1                      <---find() finds none  note atom returned 
{ 
  { 
    {42,52}             <---find_all() finds one! 
  } 
} 
{}                      <---find_all() finds none and returns an empty sequence 
-------end output

Consistency is a good thing..

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2. Re: regex.e find_all

there is an easy fix for this problem. It's not elegant but add one line of code (next to the last line below) to the function find_all() in regex.e---> 

public function find_all(regex re, sequence haystack, integer from=1, object options=DEFAULT) 
	if sequence(options) then options = or_all(options) end if 
 
	object result 
	sequence results = {} 
	while sequence(result) with entry do 
		results = append(results, result) 
		from = max(result) + 1 
 
		if from > length(haystack) then 
			exit 
		end if 
	entry 
		result = find(re, haystack, from, options) 
	end while 
	if length(results) then return results else return -1 end if 
end function
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3. Re: regex.e find_all 

Ignore my last post.  There is a more complete answer to this and another question 
in a later post.   
Subject:  regex.e find_all another problem 
 
Regards, 
jd

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