1. Re: [DOS] How to code for a time delay? - DONE
- Posted by Derek Parnell <ddparnell at bigpond.com> May 29, 2007
- 592 views
Alex Caracatsanis wrote: > }}} <eucode> > constant MAX_STARS = 200, > SCREEN = 1, > TRUE = 1, > DELAY = 0.04 -- wait 0.04 secc > > atom startTime, stopTime, interval > > startTime = 0 > stopTime = 0 > interval = (stopTime - startTime) > > for i = 1 to MAX_STARS do > puts( SCREEN, "*" ) > > -- new line/tab across every 60 characters > if remainder( i, 60 ) = 0 then > puts( SCREEN, "\n\t") > end if > > startTime = time() > while TRUE do > stopTime = time() > if (interval >= DELAY) then exit end if > end while > end for > </eucode> {{{ Your code will never work as 'interval' is always calculated as zero. Try this ...
constant MAX_STARS = 200, SCREEN = 1, TRUE = 1, DELAY = 0.04 -- wait 0.04 secc atom stopTime stopTime = 0 for i = 1 to MAX_STARS do puts( SCREEN, "*" ) -- new line/tab across every 60 characters if remainder( i, 60 ) = 0 then puts( SCREEN, "\n\t") end if stopTime = time() + DELAY while time() < stopTime do end while end for
-- Derek Parnell Melbourne, Australia Skype name: derek.j.parnell