Re: 28 or 29 days?
> Hi all,
>
> I need URGENTLY an algorithm to see is a given year is a leap year.
> Can any of you help me? I bet that in some old book it appears ;)
>
> This message sent by Daniel Berstein
I hope that you do not mind that it's in C++ code..
but, it will give you the Idea!!!
---
PogoWolf,
pogowolf at iastate.edu
HTTP://www.public.iastate.edu/~pogowolf
Off the 10Base-T, through the router, down the T3, over the Fiber line,
off the bridge, past the firewall....
Nothing but Net.
// Title: Leap Year.C
// Author: Matthew Green
// UserName: PogoWolf
// Section: L
// TA: Haverdink
//
// Started: 2/25/97
// Finished: 2/26/97
// reversion: 2/27/96
#include <fstream.h>
void main(){
int TestYear;
// Set up the years.in file for input...
ifstream infile;
infile.open ("years.in");
// Set up the years.out for output...
ofstream outfile;
outfile.open ("years.out");
// Read the years from file to test...
infile >> TestYear;
// While loop will run as long as their isa a Year to be read from infile...
while (infile){
//is TestYear a leap year?
if ((TestYear%4 == 0 && TestYear%100 != 0) || (TestYear%400 == 0 && TestYear%1
00 == 0 ))
outfile << TestYear << " IS a leap year" << endl;
else
outfile << TestYear << " is NOT a leap year" << endl;
// Get next year...
infile >> TestYear;
}// end while
} // End Main
|
Not Categorized, Please Help
|
|