OpenEuphoria

Re: regex observation & question regarding re:escape()

• Posted by _tom (admin) Sep 19, 2016
• 1420 views

My fault.

I can't find out how I got #/\*/ to work. It must have been some weird stuff I had on my computer.

I did have time to retry example 1

    include std/console.e 
 
include std/regex.e as re 
 
sequence s0 = "Payroll is $***15.00" 
display( s0 ) 
    --> Payroll is $***15.00 
    -- this is a valid Euphoria string 
    -- this IS NOT a valid regex string 
 
-- when s0 is used with the regex language 
    --> $ is a keyword 
    --> * is a keyword 
    --> . is a keyword 
 
    -- you must escape these characters before using them in a regex 
    -- then, you must escape the \ when writing a string 
 
sequence s1 = "Payroll is \\$\\*\\*\\*15\\.00" 
display( s1 ) 
    --> Payroll is \$\*\*\*15\.00 
    -- the form required when writing a regex 
 
 
-- writing a string with a ` backtik is a bit shorter 
 
sequence s2 = `Payroll is \$\*\*\*15\.00` 
display( s2) 
    --> Payroll is \$\*\*\*15\.00 
    -- the form required when writing a regex 
 
-- the Euphoria re:escape function adds the required backslashes 
-- to a sequence written with " delimiters 
sequence s3 = re:escape( s0 ) 
display( s3 ) 
    --> Payroll is \$\*\*\*15\.00 
    -- the form required when writing a regex 
 
--Note: 
-- the strings re:escape(s0), s1, and s2 are only useful as literal patterns 

thanks for pointing out my mistakes

_tom