map anomaly

new topic     » topic index » view thread      » older message » newer message
  • Posted by bugmagnet Aug 04, 2012
  • 1222 views

So a map is an atom. Ok, have got that down pat. So how does Euphoria tell the difference between an atom created with map and a normal atom? In the following code, the map and the atom resolve to the value of 1. map() claims that both are maps. And pairs gives me the same pairs that x has when given the value of y. Anomalous, no? 

include std/map.e 
 
map x = new() 
atom y = 1 
 
printf( 1, "x(a map)=%d, y(an atom)=%d\n", {x,y}) 
printf( 1, "map(x)=%d, map(y)=%d\n", {map(x),map(y)}) 
 
sequence xpairs 
sequence ypairs 
 
xpairs = pairs(x) 
ypairs = pairs(y) 
 
if equal(xpairs, ypairs) then 
	puts(1, "anomaly" ) 
else 
	puts(1, "expected" ) 
end if 


>maptest.ex 
x(a map)=1, y(an atom)=1 
map(x)=1, map(y)=1 
anomaly

Kind regards,
Bruce/bugmagnet

P.S. If this is a bug, I'm demonstrating my magnetism

new topic     » topic index » view thread      » older message » newer message

Search



Quick Links

User menu

Not signed in.

Misc Menu