1. Column Slicing Sequences
- Posted by James Powell <Wizard at DJO.COM> Apr 27, 1997
- 1046 views
Thanks guys, building a column slice by an indexed loop works, and in fact I
have already done this. I would like to point out, however, that I was not
asking for an index loop solution (I pointed that out in the first
paragraph). What I was asking was whether Euphoria could perform a column
slice of the form:
a = b[n..n+x][y]
And, as everyone pointed out, it can't. Thanks to all for the quick responses.
James Powell
(BTW, a = b[n..n+x][n..n+x] sounds fun too!)
