OpenEuphoria

newbie questions

• Posted by praufast at free.fr Mar 09, 2003
• 1149 views

Hello,

I'm new to Euphoria and my last programming was some Basic, 15 years ago at
school !
I try to access a dll ( BigSpeedZip.dll, fast zipping/unzipping) but i'm
stupidly stuck there.
The VB declare for the function  i want to use : 
'.....This function opens zip file and creates a list of items, corresponding to
'     contents of zip file. Must be called before any other function to get
access
'     to zip file. ZipName is the path and full name of zip file,
'     for example: 'C:\TEST.ZIP'. Returns zero on success.
Declare Function zOpenZipFile Lib "bszip.dll" (ByVal zipname As String) As Long

And here is a part of my EU 2.3code, win32  :
--
atom bszip
sequence ZipFile
bszip = open_dll("bszip.dll")
ZipFile="c:\\indisp.zip"
OpenZipFile = link_c_func(bszip, "zOpenZipFile",{C_CHAR}, C_INT)
ok = c_func (OpenZipFile, ZipFile)   -- error message here  "C routine
 zOpenZipFile() needs 1 argument, not 13"
-- if i put 13 C_CHAR between the braces, it hangs
-- if instead of ZipFile="c:\\indisp.zip" i write ZipFile
=open("c:\\indisp.zip", "ub") the error is "c_proc/c_func: argument list must be
a sequence ", so what to do ?
puts(1,ok) --end code
Another question : how to get the actual filename from a file number ( eg   
c:\indisp.zip vs 1342177280 ) ?

I take a look at the examples, but it didnt help me that much. Euphoria seems
really nice, so i hope to improve myself a bit...

Thanks, Phil.