OpenEuphoria

• Posted by Jacques Deschenes <desja at QUEBECTEL.COM> Jan 09, 1997
• 1798 views

--=====================_852879880==_

At 14:25 9-01-97 +0100, you wrote:
>---------------------- Information from the mail header -----------------------
>Sender:       Euphoria Programming for MS-DOS <EUPHORIA at
>MIAMIU.ACS.MUOHIO.EDU>
>Poster:       Marcel Kollenaar <M.Kollenaar at SLO.NL>
>-------------------------------------------------------------------------------
>
>Hello Jacques,
>
>Did you already solve this problem with a self made function?
>
>>
>> 2) multidimentionnal slicing, like
>>
>> let A be a 2 dimensions sequence
>> sequence B
>>
>>    B = A[2..4][3..6]
>>
>

Hi marcel,

   I didn't but your question triggered it.  See the attachement slice.ex demo

It use recursive call, as the last dimension has to be the first one to be
slice.





--=====================_852879880==_

-- slicing multidimensionals sequence


function slice(sequence s, sequence p)
-- extract a slice from n dimensions sequence
-- input:  s  sequence to slice
--         p  list of slices index in de form {{a1,a2},{b1,b2},...,{z1,z2}}

sequence cut
    if length(p) = 1 then
        return s[p[1][1]..p[1][2]]
    end if
    cut = {}
    for i = p[1][1] to p[1][2] do
        cut = append(cut,slice(s[i],p[2..length(p)]))
    end for
    return cut
end function -- slice()


sequence a, b, c

a = {1,2,3,4,5}
b = {{1,2,3,10},{4,5,6,11},{7,8,9,12}}
c = {b*2,b*3,b+23}

puts(1,"a = ")
? a
puts(1,"a[2..4] = ")
? slice(a,{{2,4}})
puts(1,"b = ")
? b
puts(1,"b[2..3][2..4] = ")
? slice(b,{{2,3},{2,4}})
puts(1,"c = ")
? c
puts(1,"c[1..2][2..3][1..1] = ")
? slice (c,{{1,2},{2,3},{1,1}})


--=====================_852879880==_

Jacques Deschenes
Baie-Comeau, Quebec
Canada
desja at quebectel.com

--=====================_852879880==_--