OpenEuphoria

Re: optimization....help

• Posted by jiri babor <jiri_babor at HOTMAIL.COM> Oct 21, 2000
• 543 views

Euman, this will be somewhat faster:

for x = 1 to down do
     seq[x] = r[count..across]
     count  = across + 1
     across += 262
end for

jiri


>From: Euman <euman at BELLSOUTH.NET>
>Reply-To: Euphoria Programming for MS-DOS <EUPHORIA at LISTSERV.MUOHIO.EDU>
>To: EUPHORIA at LISTSERV.MUOHIO.EDU
>Subject: optimization....help
>Date: Fri, 20 Oct 2000 22:59:33 -0400
>
>Hello all,
>
>Can the below loop be optimized further?
>
>I know that takeing the multiplies out should do it
>but am at a lose on this.......
>
>----- begin -----------
>
>count = 1
>across = 262
>down = 236
>
>seq = repeat(0,down)
>
>for x = 1 to down do
>     seq[x] = r[count..across * x]
>     count  = across * x + 1
>end for
>
>--- end -------------------
>
>euman at bellsouth.net
>

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