Why won't THIS work? (2)
- Posted by Robert Craig <robert_craig at COMPUSERVE.COM> Mar 10, 1997
- 1029 views
Joseph Martin writes: > printf(1, "%f", real[3]) gives > 6.000000 > BUT when I give this command: > printf(1, "%d", real[3]) I get > 5 as the output. I suspect that real[3] is really 5.99999999999999... "%f" format rounds to 6 decimal places by default. When you use %d format it simply truncates it down to an integer rather than rounding it. Use "%.0f" (that's point *zero*) instead of "%d". You'll get the value displayed as an integer with no decimal places and no decimal point. i.e. you'll see: 6 Regards, Rob Craig Rapid Deployment Software