Re: Probability question

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That's Combinatorics Chris.

The number possible combinations with three three-sided random generators is 3^3 = 27. Now the sets we are interested in are where you pick three values out of three. The first value one of the three, the second value is one of the two that are left, and the last has only one possible value after you check that. So that's 3 * 2 * 1 (=6).

Now what if you had six coins and you wanted to have of three of them heads and three of them tails. How many ways can that happen with that restriction? How many ways can you flip six coins generally speaking? The former question is harder of course.

Pete, read this site: http://www.coolmath.com/algebra/20-combinatorics/01-counting-principals-01

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