Re: Probability question
- Posted by Spock Jan 16, 2019
- 1506 views
Just being curious.
Suppose I have a bucket containing 1001 7-sided dice. When I tip them out and count them,
what is the probability of getting exactly 143 of each face?
If I remember probability correctly ...
If you throw one die, the probability of one face coming up is 1/7. If you throw another die, and you want the same face to come up, the joint probability is (1/7) * (1/7), or (1/7)2. Continuing for 1001 dice, the probability should be (1/7)1001, or approximately zero. :)
Correct me if I am wrong!
I think your result would then need to be divided by some value since each clump of 143 has 7 possibilities that would satisfy the condition.
If there are 7 entities that each have 7 states, in the total number of permutations, how many monotonic groups would there be? 7! ?
So I'm feeling that the answer lies more towards: 1 in 7 ^ 1001 / 7!
Spock
